C语言训练-斐波纳契数列

参考代码:

#include <bits/stdc++.h>

using namespace std;

int main(int argc, char** argv) {

int n,a=1,b=1,c;

cin>>n;

if(n==1){

cout<<a;

}

else{

cout<<a<<" "<<b<<" ";

for(int i=1;i<=n-2;i++){

c=a+b;

a=c;

b=a-b;

cout<<c<<" ";

}

}

return 0;

}