编写题解 1141: C语言训练-百钱百鸡问题

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int main()

{

int cock=0, hen=0, chicken=99;

for (; cock < 20; cock++)

{

chicken = 33;

for (; chicken >=0; chicken--)

{

if (2 * cock + 200 == chicken*8&&(100-cock-3*chicken)>0)

{

hen = 100 - cock - 3 * chicken;

printf("cock=%d,hen=%d,chicken=%d\n", cock, hen, chicken*3);

break;

}

}

}

return 0;

}