十->二进制转换-题解（C语言代码）

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int main()

{

long long int num, n[32], t, i, j, m;

while (scanf("%lld", &num) != EOF) {

m = 0;

t = num;

if (num < 0) {

num = -num;

}

for (i = 15;num>0; i--) {

n[i] = num % 2;

num /= 2;

}

for (j = i+1; j < 16; j++) {

m = m * 10 + n[j];

}

if (t < 0) {

printf("%lld-->%lld\n",t ,-m);

}

else {

printf("%lld-->%lld\n", t, m);

}

}

return 0;

}