[编程入门]自定义函数之字符类型统计-题解（C语言代码）

解题思路:同时传入两个数组，第二个数组用于带出数据

注意事项:

参考代码:

#include "stdio.h"

int count(char *arr,int *fina,int n);

int main(int argc, char const* argv[])

{

    char arr[100] = { '!','@','#','$','%','^','Q','W','E','R','T',' ',' ',' ',' ','1','2','3','4','5','6','7','\0' };

    int n = 100,fina[4];//定义一个数组，用来带出四个数据

    gets(arr);//接收字符

    count(arr,fina,n);

    printf("%d %d %d %d\n",fina[0],fina[1],fina[2],fina[3] );

    return 0;

}

int count(char *arr,int *fina,int n)

{

     int cha = 0, num = 0, space = 0, els = 0;

     for (int i = 0; i < n,arr[i] !='\0'; ++i)//循环100次，当其中一个字符为'\0'退出

         {

             if (arr[i] >= 'a' && arr[i]

                  cha++;

             else if (arr[i] >= '0' && arr[i] <= '9') //数字

                 num++;

             else if (arr[i] == ' ') //空格

                  space++;

             else //其它

                 els++;

        }

     *fina = cha;                 *(fina+1) = num;

     *(fina+2) = space;     *(fina+3) = els;//把数据存入数组   

     return 0;

}