解题思路:
不区分大小写的话如果字符一致,那ASCII码的差值肯定是32的倍数;不是倍数的话则字符不同
注意事项:
参考代码:
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); String s1 = in.next(); String s2 = in.next(); int k = 0; int l = 0; int h = 0; if(s1.length() != s2.length()){ System.out.println("1"); }else{ for(int i = 0;i<s1.length();i++){ if(s1.charAt(i)==s2.charAt(i)){ k++; }else{ l = s1.charAt(i)-s2.charAt(i); h+=Math.abs(l); } } if(k==s1.length()){ System.out.println("2"); }else if(h%32 == 0){ System.out.println("3"); }else{ System.out.println("4"); } } } }
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