c++简单解法

#include <iostream>

using namespace std;

int main() {

int n;

cin >> n;

int sumjin = 0, sumyin = 0, sumtong = 0;\\求和定义一定要初始化

for (int i = 0; i < n; i++) {

int a, b, c;   \\内部定义，随意

cin >> a >> b >> c;

sumjin += a;   \\循环求和赋值给需求和定义

sumyin += b;

sumtong += c;

}

int sum = sumjin + sumyin + sumtong;

cout << sumjin << " " << sumyin << " " << sumtong << " " << sum << endl;

return 0;

}