循环控制，汽水瓶

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int test1(int n) {

    return n / 3;

}

int test2(int n) {

        return n % 3;

}

int main() {

    int n;

    int count = 0,a1=0;

    while (~scanf_s("%d", &n)) {

            if (n == 0)break;

            while (1) {

                    count += test1(n);

                    a1 = test2(n);//剩余空数量

                    //printf("%d %d ", count, a1);

                    int t = test1(n) + a1;

                    if (t == 2) {

                            count++;

                            break;

                    }

                    else if (t == 0||t == 1) {

                            break;

                    }

                    else {

                            n = n - test1(n) * 3 + test1(n);

                            if (n == 2) {

                                    break;

                            }

                    }

            }

            printf("%d\n", count);

            count = 0;

    }

return 0;

}