1028: [编程入门]自定义函数求一元二次方程

解题思路:

注意事项:

参考代码:

#include<bits/stdc++.h>

double sum1,m;

double jie(int a,int b,int c)

{

m=b*b-4*a*c;

sum1=sqrt(m)/(2*a);

return sum1;

}

double jie1(int a,int b,int c)

{

m=b*b-4*a*c;

m=-m;

sum1=sqrt(m)/(2*a);

return sum1;

}

int main()

{

double a,b,c;

scanf("%lf %lf %lf",&a,&b,&c);

double q=-b/(2*a);

double m=b*b-4*a*c;

if(m<0)

{

jie1(a,b,c);

printf("x1=%.3lf+%.3lfi x2=%.3lf-%.3lfi",q,sum1,q,sum1);

}

if(m>=0)

{

jie(a,b,c);

printf("x1=%.3lf+%.3lfi x2=%.3lf-%.3lfi",q,sum1,q,sum1);

}

return 0;

}