一遍写完,没做优化,跟着代码走读就能理解
参考代码:
#include <stdio.h> void InitBoard(char board[100][100], int row, int col) { getchar();//取\n int i = 0; int j = 0; for (i = 1; i <= row; i++) { for (j = 1; j <= col; j++) { board[i][j] = getchar(); } getchar();//取\n } } int get_count(char board[100][100], int i, int j) { int count = 0; if (board[i-1][j-1] == '*') count++; if (board[i-1][j] == '*') count++; if (board[i-1][j+1] == '*') count++; if (board[i][j-1] == '*') count++; if (board[i][j] == '*') count++; if (board[i][j+1] == '*') count++; if (board[i+1][j-1] == '*') count++; if (board[i+1][j] == '*') count++; if (board[i+1][j+1] == '*') count++; return count+48;//char类型,于是通过ASCII码表来转换 0 + 48 = '0' } void CheckBoard(char board[100][100], int row, int col) { int i = 0; for (i = 1; i <= row; i++) { int j = 0; for (j = 1; j <= col; j++) { if (board[i][j] == '*') { continue; } else { board[i][j] = (char)get_count(board, i, j); } } } } void print(char board[100][100], int row, int col, int count) { printf("Field #%d:\n", count); int i = 0; for (i = 1; i <= row; i++) { int j = 0; for (j = 1; j <= col; j++) { printf("%c", board[i][j]); } printf("\n"); } printf("\n"); } int main(void) { int row, col; char board[100][100] = {0}; int count = 1; while (~scanf("%d%d", &row, &col)) { if (row == 0 && col == 0) { return 0; } InitBoard(board, row, col); CheckBoard(board, row, col); print(board, row, col, count); count++; } return 0; }
0.0分
0 人评分
C语言程序设计教程(第三版)课后习题8.2 (Java代码)浏览:2287 |
这可能是一个假的冒泡法浏览:1071 |
不会做的浏览:954 |
用筛法求之N内的素数。 (C语言代码)浏览:1386 |
C语言程序设计教程(第三版)课后习题1.5 (C语言代码)浏览:644 |
C语言程序设计教程(第三版)课后习题7.4 (C语言代码)浏览:1314 |
C语言程序设计教程(第三版)课后习题6.5 (C++代码)浏览:487 |
简单的a+b (C语言代码)浏览:878 |
永远的丰碑 (C语言代码)浏览:608 |
母牛的故事 (C语言代码)浏览:625 |