生日日数——python

解题思路:

注意事项:

参考代码:

def f(year1):
   if (year1 % 100 != 0 and year1 % 4 == 0) or year1 % 400 == 0:
       return 1
   else:
       return 0


results = []

month_r = {1: 31, 2: 29, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31}
month_p = {1: 31, 2: 28, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31}

month_ = list()
month_.append(month_p)
month_.append(month_r)

while True:
   over_days = 10000
   try:
       year, month, day = map(int, input().split())
   except:
       break
   else:
       if f(year) == 1:
           for m in range(month+1, 13):
               over_days -= month_r[m]
           over_days -= (month_r[month] - day)
       else:
           for m in range(month+1, 13):
               over_days -= month_p[m]
           over_days -= (month_p[month] - day)

       year += 1
       month = 1
       day = 1

       while over_days > 365 + f(year):
           over_days -= 365 + f(year)
           year += 1

       for moo in range(1, 13):
           if over_days > month_[f(year)][moo]:
               over_days -= month_[f(year)][moo]
           else:
               month = moo
               break

       results.append(f"{year}-{month}-{over_days}")

for result in results:
   print(result)