解题思路:把庚子年作为开始年,每过60年一个循环
注意事项:正年数与负年数方向不一样(2019 是己亥年 2021是辛丑年)都与2020差一年
参考代码:
#include <iostream> #include <algorithm> #include <cstdio> #include <string> using namespace std; string tian_gan[10]={"geng","xin","ren","gui","jia","yi","bing","ding","wu","ji"}; string di_zi[12]={"zi","chou","yin","mao","chen","si","wu","wei","shen","you","xu","hai"}; int main() { int y,n; cin>>y; n=(y-2020)%60; if(n>=0) // 如果年数是正整数从前往后找 cout<<tian_gan[n%10]<<di_zi[n%12]<<endl; else // 负整数从后往前找 cout<<tian_gan[10+n%10]<<di_zi[12+n%12]<<endl; return 0; }
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