解题思路:把庚子年作为开始年,每过60年一个循环
注意事项:正年数与负年数方向不一样(2019 是己亥年 2021是辛丑年)都与2020差一年
参考代码:
#include <iostream> #include <algorithm> #include <cstdio> #include <string> using namespace std; string tian_gan[10]={"geng","xin","ren","gui","jia","yi","bing","ding","wu","ji"}; string di_zi[12]={"zi","chou","yin","mao","chen","si","wu","wei","shen","you","xu","hai"}; int main() { int y,n; cin>>y; n=(y-2020)%60; if(n>=0) // 如果年数是正整数从前往后找 cout<<tian_gan[n%10]<<di_zi[n%12]<<endl; else // 负整数从后往前找 cout<<tian_gan[10+n%10]<<di_zi[12+n%12]<<endl; return 0; }
0.0分
0 人评分
C语言程序设计教程(第三版)课后习题8.3 (C语言代码)浏览:617 |
C语言程序设计教程(第三版)课后习题12.1 (C语言代码)浏览:978 |
C语言程序设计教程(第三版)课后习题1.5 (C语言代码)浏览:520 |
C语言程序设计教程(第三版)课后习题8.1 (C语言代码)浏览:438 |
C语言程序设计教程(第三版)课后习题5.6 (C语言代码)浏览:850 |
大神老白 (C语言代码)浏览:640 |
printf基础练习2 (C语言代码)浏览:644 |
C语言考试练习题_一元二次方程 (C语言代码)浏览:575 |
蛇行矩阵 (C语言代码)浏览:524 |
用筛法求之N内的素数。 (C语言代码)浏览:664 |