解题思路:
正常思路
注意事项:
本题难点在于按对角线输出时的情况
①输出左对角线时,定位第一个输出的下标
while(x != 1 and y != 1):
x = x - 1
y = y - 1
②输出右对角线时,定位第一个输出的下标
while(x != n and y != 1):
x = x + 1
y = y - 1
while循环控制防止过界
定位好第一个下标之后接下来按格式输出就好了。
参考代码:
def f(n,i,j): for y in range(1,n+1): print('({},{})'.format(i,y),end='') print() for x in range(1,n+1): print('({},{})'.format(x,j),end='') print() x = i y = j while(x != 1 and y != 1): x = x - 1 y = y - 1 while(1<= x <= n and 1<= y <= n): print('({},{})'.format(x,y),end='') x = x + 1 y = y + 1 print() x = i y = j while(x != n and y != 1): x = x + 1 y = y - 1 while(1<= x <= n and 1<= y <= n): print('({},{})'.format(x,y),end='') x = x - 1 y = y + 1 if __name__ == '__main__': n = int(input()) i = int(input()) j = int(input()) f(n,i,j)
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