[编程入门]利润计算-用switch语句的题解（C语言）

解题思路:大家的题解都是if语句，小白初学，想了另外一个思路，用switch语句写了也可运行，个人觉得比较简洁，希望大神们来指正一下！！！

注意事项:

参考代码:

#include<stdio.h>

int main()

{

    int x,y=0,n;

    scanf("%d",&x);

    switch(n=x/100000)

            {

               case 10:    case 9:   case 8:

               case 7:   case 6:

                   y=y+(x-600000)*0.015;

                   x=600000;

               case 5:   case 4:

                   y=y+(x-400000)*0.03;

                   x=400000;

               case 3:   case 2:

                   y=y+(x-200000)*0.05;

                   x=200000;

               case 1:

                   y=y+(x-100000)*0.075;

                   x=100000;

               case 0:

                   y=y+x*0.1;

                   printf("%d",y);

                   break;

               default:                                                                 //高于10w的情况

                   y=(x-1000000)*0.01+39500;

                   printf("%d",y);

                   break;

            }

            return 0;

}