原题链接:小O的数字
解题思路:
注意事项:
参考代码:
#include<stdio.h>
void Paint(unsigned long a,int i)
{
char zeno[5][4]={"***","* *","* *","* *","***"};
char one[5][4]={" *"," *"," *"," *"," *"};
char two[5][4]={"***"," *","***","* ","***"};
char three[5][4]={"***"," *","***"," *","***"};
char four[5][4]={"* *","* *","***"," *"," *"};
char five[5][4]={"***","* ","***"," *","***"};
char six[5][4]={"***","* ","***","* *","***"};
char seven[5][4]={"***"," *"," *"," *"," *"};
char eight[5][4]={"***","* *","***","* *","***"};
char nine[5][4]={"***","* *","***"," *","***"};
switch(a)
{
case 0:
printf("%s",zeno[i]);
break;
case 1:
printf("%s",one[i]);
break;
case 2:
printf("%s",two[i]);
break;
case 3:
printf("%s",three[i]);
break;
case 4:
printf("%s",four[i]);
break;
case 5:
printf("%s",five[i]);
break;
case 6:
printf("%s",six[i]);
break;
case 7:
printf("%s",seven[i]);
break;
case 8:
printf("%s",eight[i]);
break;
case 9:
printf("%s",nine[i]);
break;
}
}
int main()
{
unsigned long n;
int N[20],i,j,m,flag;
char zeno[5][4]={"***","* *","* *","* *","***"};
while(scanf("%ul",&n)!=EOF)
{
flag=0;
if(n==0)//别忘了0
{
flag=1;
for(i=0;i<5;i++)
{
printf("%s\n",zeno[i]);
}
}
i=0;
while(n!=0)//求出每一位数字
{
N[i]=n%10;
n=n/10;
i++;
}
m=i;
for(i=0;i<5;i++)
{
for(j=m-1;j>=0;j--)
{
Paint(N[j],i);
if(j!=0)//数字和数字之间空一列
printf(" ");
}
if(flag==0)
printf("\n");
}
}
return 0;
}0.0分
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