【出圈】 （C++代码）简单循环

解题思路:





注意事项:





参考代码:

#include<iostream>
using namespace std;
long Josephus(long,long,long);
int main()
{
    int m,n;
    while(cin>>n>>m)
        cout<<Josephus(m,n,1)<<endl;
    return 0;
}
long Josephus(long m,long n,long k)
{
    long x;
    for(long i=1;i<=n;i++)
        {
            if((k+m)<i)
            {
                x=(k-1)/(i-m);
                if(i+x<n)
                {
                    k=k+m*x;
                    i=i+x;
                }
                else
                {
                    k=k+m*n-i;
                    i=n;
                }
            }
            k=(k+m-1)%i+1;
        }
    return k;
}