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Where there is a will, there is a way.
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屌丝程序狗
作者: Liamcoder 发表时间:2017-07-07 18:16:21 浏览:575 | 评论:0
#include<stdio.h>
#define LEAP_YEAR(y) ((y%4==0&&y%100!=0)||y%400==0)?'L':'N';
int main()
{
int y;
char ch;
scanf("%d", &y);
ch = LEAP_YEAR(y);
printf("%c", ch);
return 0;
}
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