结构体之成绩统计2（小白也能看懂）

解题思路:

   先定义结构体，再for循环给结构体赋值

1. 然后定义三个sum分别计算三门科目总分，再通过每门科目总分求每门的平均分

2. 定义一个·变量，然后通过for循环确定最高分为多少，然后通过for循环比对出最高分所对应的人，并输出打印。
   
   注意事项:

   参考代码:

#include<stdio.h>

typedef struct Student

{

char studentID[100];

char name[100];

int Chinese;

int Maths;

int English;

}S[100];

S student[100];

int main()

{

int n;

scanf("%d", &n);

for (int i = 0; i < n; i++)

{

scanf("%s %s %d %d %d", &student[i]->studentID, &student[i]->name, &student[i]->Chinese, &student[i]->Maths, &student[i]->English);

}

int sum1 = 0;

int sum2 = 0;

int sum3 = 0;

for (int i = 0; i < n; i++)

{

sum1 += student[i]->Chinese;

sum2 += student[i]->Maths;

sum3 += student[i]->English;

}

int num[100];

for (int i = 0; i < n; i++)

{

num[i] = student[i]->Chinese + student[i]->Maths + student[i]->English;

}

int ave1 = sum1 / n;

int ave2 = sum2 / n;

int ave3 = sum3 / n;

printf("%d %d %d\n", ave1, ave2, ave3);

int max = num[0];

for (int i = 0; i < n; i++)

{

if (max < num[i])

{

max = num[i];

}

}

for (int i = 0; i < n; i++)

{

int count = student[i]->Chinese + student[i]->Maths + student[i]->English;

if (max == count)

{

printf("%s %s %d %d %d", student[i]->studentID, student[i]->name, student[i]->Chinese, student[i]->Maths, student[i]->English);

}

}

return 0;

}