1183: 人见人爱A+B(atoi函数的使用）

解题思路:

注意事项:

参考代码:

#include<iostream>

#include<cstring>

using namespace std;

int main()

{

int T;

cin >> T;

while (T--)

{

char s[100];

int arr[7] = { 0 };

for (int i = 1; i <= 6; i++)

{

cin >> s;

getchar();//将空格给消掉

arr[i] = atoi(s);//将数字字符串转化为数字

}

int s1 = arr[1]+arr[4];

int s2 = arr[2]+arr[5];

int s3 = arr[3]+arr[6];

if (s3 >= 60)

{

s2 += s3/60;

s3 %=60;

}

if (s2 >= 60)

{

s1 += s2/60;

s2 %=60;

}

cout << s1 << " " << s2 << " " << s3 << endl;

}

return 0;

}