C++宏定义闰年判断
摘要：解题思路:闰年：能被4但不能被100整除 或 能被400整除注意事项:宏定义换行要用\参考代码:#include<iostream>using name……
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摘要：解题思路:注意事项:参考代码:#include<iostream>using namespace std;int main(){ int a; &nb……
[编程入门]宏定义之闰年判断
摘要：解题思路:注意事项:参考代码:#include <stdio.h>#define LEAP_YEAR(year)\{\ if((year % 4 == 0 &am……
[编程入门]宏定义之闰年判断
摘要：解题思路:注意事项:参考代码:#include<stdio.h>#define LEAP_YEAR(y) yearint main(){ int year=0;&……
C++简单写法--------------------------------------
摘要：解题思路:注意事项:参考代码:#include<iostream>using namespace std;bool is_leap(int year){ if (……
1039: [编程入门]宏定义之闰年判断(python)
####~~~pythondefislun(n):ifn%4==0andn%100!=0:return'L'ifn%400==0:return'L'return'N'defmain():n=int(input())print(islun(n))if__name__=='__main__':main()