![[编程入门]阶乘求和-题解(Java代码)](https://blog.dotcpp.com/assets/img/Dotcpp.png)
[编程入门]阶乘求和-题解(Java代码)
本来用的是变量用的都是整型变量，结果测试数字13开始发现溢出了在这题里面学到了注意溢出0.0不亏publicclasstext{publicstaticvoidmain(Stringargs[]){Scannercin=newScanner(System.in);intn=cin.nextInt();
[编程入门]阶乘求和-题解(C语言代码)
摘要：```c
#include
int main()
{
long sum = 0,m=1; //注意sum，m超过int范围
int i,n;
scanf("%d",&n);
……
[编程入门]阶乘求和-题解(Java代码)
**这个题不是很简单嘛？我透怎么这么多没做出来的？？？？？？？蜜汁问题！！！代码如下：```javapublicstaticvoidmain(String[]args){Scannersc=newScanner(System.in);intn=sc.nextInt();longsum=1;longss
[编程入门]阶乘求和-题解(C++代码)
记得存储阶乘时和阶乘求和时要用long类型！！！```cpp#includeusingnamespacestd;longfact(intn_int){longjc_int=1;for(inti_for1_int=1;i_for1_int>n_int;longsum_int=0;for(inti_for
[编程入门]阶乘求和-题解(Java代码)
packagepractice.C;importjava.util.Scanner;/***阶乘求和**@author涂图**/publicclassMain{publicstaticvoidmain(String[]args){Scannerin=newScanner(System.in);whil
[编程入门]阶乘求和-题解(C++代码)
```cpp#includeusingnamespacestd;intmain(){intn=0;longlongsum=0,num=1;//当n=19时会超出int的范围，所以选用ll。cin>>n;for(inti=1;i
[编程入门]阶乘求和-题解(Java代码)递归和循环实现
```Javapublicstaticvoidmain(String[]args){Scannersc=newScanner(System.in);intn=sc.nextInt();longsum=0;for(inti=1;i
[编程入门]阶乘求和 （Java代码）
importjava.util.Scanner;publicclassMain{publicstaticvoidmain(String[]args){longa,c=1,y=1,v=1;Scannerscanner=newScanner(System.in);intx=scanner.nextInt(
[编程入门]阶乘求和-题解(C++代码)
#细节不能用**int**类型存储结果，会发生**overflow**。使用**longlong**类型。#代码```cpp#includeintmain(){intn;std::cin>>n;//int类型会溢出longlongsn=0,an=1;for(inti=1;i
[编程入门]阶乘求和-题解(Java代码)
本题难度不大：注意细节（应当注意定义类型为long如果为int则显示答案为正确率百分之五十，应为后面会超出int取值范围)importjava.util.Scanner;publicclassT1014{publicstaticvoidmain(String[]args){Scannerscanner