C语言训练-尼科彻斯定理 （C++代码）

解题思路:

注意事项:

参考代码:

#include <iostream>

using namespace std;

void fun(int m)

{

for (int i = 1,num = m * m + 1- m; i <= m; i++,num += 2)

{

if (i == 1)

{

if (m != 1)

cout << m << "*" << m << "*" << m << "=" << m * m * m << "=" << num << "+";

else

cout << m << "*" << m << "*" << m << "=" << m * m * m << "=" << num;

}

else if (i == m)

cout << num;

else

cout << num << "+";

}

return;

}

int main(int argc, char** argv)

{

int m = 0;

cin >> m;

fun(m);

return 0;

}