结构体之时间设计

解题思路:

注意事项:

参考代码:

#include <bits/stdc++.h>

using namespace std;

int judge(int n) 

{

    if (n % 4 == 0 && n % 100 != 0 || n % 400 == 0) 

    {

        return 1;//闰年返回1

    } 

    else

     {

        return 0;//平年返回0

    }

}

int main()

 {

    int MONTH[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

    int sum = 0;

    struct date

     {

        int year;

        int month;

        int day;

     }DATE;

    cin >> DATE.year >> DATE.month >> DATE.day;

    if (judge(DATE.year) == 1) 

    {

        MONTH[2] = 29;

    }

    for (int i = 1; i < DATE.month; i++)

     {

        sum += MONTH[i];

    }

    sum += DATE.day;

    cout << sum;

    return 0;

}