母牛的简单解法C语言

int number_cow(int year)

{

    int number[55],i;

    number[0] = 0;

    number[1] = 1;

    number[2] = 2;

    number[3] = 3;

    for(i=4; i<=55; i++)

    {

        number[i] = number[i-1]+number[i-3];

    }

    return number[year];

}

int main()

{

int year;

scanf("%d",&year);

while(year != 0)

    {

        printf("%d\n",number_cow(year));

        getchar();

        scanf("%d",&year);

    }

    return 0;

}