c语言代码解决问题

解题思路:

注意事项:

参考代码:

#include<stdio.h>

#include<stdlib.h>

int main()

{

int n, i, j;

double* a,aver,sum=0.0;

scanf("%d", &n);

a = (double*)malloc(sizeof(double) * n);

for (i = 0; i < n; i++)

{

scanf("%lf", &a[i]);

sum += a[i];

}

aver = sum / (double)n;

printf("%.0lf %.5lf", sum, aver);

return 0;

}