c语言代码解决问题

解题思路:

注意事项:

参考代码:

#include<stdio.h>

int main()

{

    int a[20][20], n, i, j, sum[40] = {0}, k = 0,l=0;

    scanf("%d", &n);

    for (i = 0; i < n; i++)

        for (j = 0; j < n; j++)

            scanf("%d", &a[i][j]);

    for (i = 0; i < n; i++)

    {

        int count = 0;

        for (j = 0; j < n; j++)

        {

            count += a[j][i];

        }

        if (count > n / 2)

        {

            sum[k] = i + 1;

            k++;

        }

    }

    for (i = 0; i < k - 1; i++)

    {

        for (j = 0; j < k - i - 1; j++)

        {

            if (sum[j] > sum[j + 1])

            {

                int temp;

                temp = sum[j];

                sum[j] = sum[j + 1];

                sum[j + 1] = temp;

            }

        }

    }

    for (i = 0; i < k - 1; i++)

    {

        if (sum[i] != sum[i + 1])

        {

            printf("%d ", sum[i]);

        }

    }

    printf("%d", sum[k - 1]);

    return 0;

}