【c++】蛇形矩阵简单易懂

解题思路:本蒟蒻想到了先建立出一个不少于100x100的蛇形矩阵保存，在根据用户所输入的行列数进行输出。

注意事项:输出的行列数

参考代码:

#include <iostream>
#include <bits/stdc++.h>

using namespace std;

int main()
{
    int s[105][105];
    int n = 105;
    int t = 1,m = 0,j = 0;
    int bn;
    bn = n;
    for(int i = 0;i<n;i++)
    {
        for(int j = 0;j<n;j++)
        {
            s[i][j] = 0;
        }
    }
    for(int i = 0;i<n;i++)
    {
        if( i == 0)
        {
            s[i][0] = 1;
        }
        else
        {
            s[i][0] = s[i - 1][0] + m;
        }
        t = s[i][0] + 1;
        for(int j = 1;j<bn;j++)
        {
            s[i][j] = s[i][j - 1] + t;
            t = t + 1;
        }
        m = m + 1;
        bn--;
    }
    bn = n - 1;
    m = 2;
    for(int j = 1;j<bn - 1;j++)
        {
            t = m;
            for(int k = 1;k<n - 1;k++)
            {
                s[k][j] = s[k - 1][j] + t;
                t++;
            }
            bn--;
            t++;
            m++;
        }
    while(cin>>n)
    {
        bn = n;
       for(int i = 0;i<n;i++)
        {
            for(int j = 0;j<bn;j++)
            {
                if(s[i][j] != 0)
                {
                   cout<<s[i][j]<<" ";
                }
            }
            bn--;
            cout<<endl;
        }
    }
}