自定义函数之字符类型统计

解题思路:主要是如果满足if就直接continue不用再跑下段代码了可以少些条件

注意事项:无

参考代码:

#include <iostream>

#include <string>//要用到getline输入空格

using namespace std;

int main()

{

int a = 0, b = 0, c = 0, d = 0;//计数

string s;

getline(cin, s);

for (int i = 0; i < s.size(); i++)

{

if ('a' <= s[i] && s[i] <= 'z' || 'A' <= s[i] && s[i] <= 'Z')

{

a++;

continue;

}if ('0' <= s[i] && s[i] <= '9')

{

b++;

continue;

}

if (s[i] == ' ')

{

c++;

continue;

}

d++;

}

cout << a << ' ' << b << ' ' << c << ' ' << d;

return 0;

}