通俗易懂的C++方法

解题思路:

注意事项:

参考代码:

#include <iostream>

using namespace std;

int main() {

int m, n;

int s1 = 0;

int s2 = 0;

int s3 = 0;

cin >> m;

for (int i = 0; i < m; i++) {

cin >> n;

if (n == 1)

s1++;

else if (n == 5)

s2++;

else if (n == 10)

s3++;

}

cout << s1<<endl;

cout << s2<<endl;

cout << s3<<endl;

}