C语言训练-阶乘和数* 笨方法

解题思路:先将符合条件的数字找出来，放在一个数组里，再来排序。希望对大家要帮助

参考代码:

#include<stdio.h>

int R1(int n)

{

int sum2 = 1;

for (; n > 0; n--)

{

sum2 = sum2 * n;

}

return (sum2);

}

int R2(int n)

{

int sum1 = 0, t = 0;

while (n != 0)

{

t = n % 10;

sum1= sum1+ R1(t);

n = n / 10;

}

return (sum1);

}

int R3(int n)

{

int s = 0;

while (n != 0)

{

s = n % 10;

n = n / 10;

}

return (s);

}

int main()

{

int i, j, a[10], n = 0, t = 0;

for (i = 1; i <= 100000; i++)

{

if (R2(i) == i)

{

a[n] = i;

n++;

}

}

for (i = 0; i <=( n-1); i++)

{

for (j = i + 1; j <= (n-1); j++)

{

if (R3(a[i]) > R3(a[j]))

{

t = a[i];

a[i] = a[j];

a[j] = t;

}

}

}

for (i = 0; i <= (n-1); i++)

printf("%d ", a[i]);

return 0;

}