最原始的求

解题思路:

注意事项:

参考代码:

#include<stdio.h>

#include<math.h>

int main()

{

int a,b,c,d,e,n;

scanf("%d",&n);

int result;

result = log10(n)+1;

printf("%d\n",result);

if(result==5)

{ 

a= n/10000;

b= (n%10000)/1000;

c= (n%1000)/100;

d=(n%100)/10;

e=n%10;

printf("%d %d %d %d %d\n",a,b,c,d,e);

a=n%10;

b=(n%100)/10;

c=(n%1000)/100;

d=(n%10000)/1000;

e=n/10000;

printf("%d%d%d%d%d\n",a,b,c,d,e);

}

if(result==4)

{

a=n/1000;

b=(n%1000)/100;

c=(n%100)/10;

d=(n%10);

printf("%d %d %d %d\n",a,b,c,d);

a=n%10;

b=(n%100)/10;

c=(n%1000)/100;

d=n/1000;

printf("%d%d%d%d\n",a,b,c,d);

}

if(result==3)

{

a=n/100;

b=(n%100)/10;

c=(n%10);

printf("%d %d %d\n",a,b,c);

a=n%10;

b=(n%100)/10;

c=n/100;

printf("%d%d%d",a,b,c);

}

if(result==2)

{

a=n/10;

b=n%10;

printf("%d %d\n",a,b);

a=n%10;

b=n/10;

printf("%d%d\n",a,b);  

}

if(result==1)

{

a=n;

printf("%d \n",a);

a=n;

printf("%d\n",a); 

}

return 0; 

}