解题思路:

之前在洛谷上有类似的题

注意事项:

注意每行字符的空格数,多一个都不行

参考代码:

#include <iostream>
using namespace std;
int main()
{
    cout << "                ********\n"
            "               ************\n"
            "               ####....#.\n"
            "             #..###.....##....\n"
            "             ###.......######              ###                 ###           ###           ###\n"
            "                ...........               #...#               #...#         #...#         #...#\n"
            "               ##*#######                 #.#.#               #.#.#         #.#.#         #.#.#\n"
            "            ####*******######             #.#.#               #.#.#         #.#.#         #.#.#\n"
            "           ...#***.****.*###....          #...#               #...#         #...#         #...#\n"
            "           ....**********##.....           ###                 ###           ###           ###\n"
            "           ....****    *****....\n"
            "             ####        ####\n"
            "           ######        ######\n"
            "##############################################################              ##################################\n"
            "#...#......#.##...#......#.##...#......#.##------------------#              #...#......#.##------------------#\n"
            "###########################################------------------#              ###############------------------#\n"
            "#..#....#....##..#....#....##..#....#....#####################              #..#....#....#####################\n"
            "##########################################    #----------#                  ##############    #----------#\n"
            "#.....#......##.....#......##.....#......#    #----------#                  #.....#......#    #----------#\n"
            "##########################################    #----------#                  ##############    #----------#\n"
            "#.#..#....#..##.#..#....#..##.#..#....#..#    #----------#                  #.#..#....#..#    #----------#\n"
            "##########################################    ############                  ##############    ############\n";
    return 0;
}


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