三个数字的排序(C++)萌新也能打的通俗易懂

解题思路:探讨三个数之间的对应关系。用穷举法即可。
注意事项:不要数漏！不要数漏！不要数漏！因为只有3个数所以很容易举列，所以只适用于简易的排列。

参考代码:

#include<iostream>

using namespace std;

int main(){

int a,b,c;

cin >> a >> b >>c;

if(a<b && b<c){

cout << a <<" "<< b <<" "<< c;

}else if(b<a && a<c){

cout << b <<" "<< a <<" "<< c;

}else if(c<a && a<b){

cout << c <<" "<< a <<" "<< b;

}else if(a<c && c<b){

cout << b <<" "<< a <<" "<< c;

}else if(b<c && c<a){

cout << b <<" "<< a <<" "<< c;

}else{

cout << c <<" "<< b <<" "<< a;

}

return 0;

}