A+B for Input-Output Practice （C++代码）

#include<iostream>

using namespace std;

int main()

{

int n,m, x,l=0, s = 0,a[10000];

cin >> n;

for(int i=0;i<n;i++)

{

cin >> m;

for (int k = 0; k < m; k++)

{

cin >> x;

s += x;

}

a[l] = s;

s = 0;

l++;

}

for (int j = 0; j < n; j++)

cout << a[j] << endl << endl;

return 0;

}