1009题解: 数字的处理与判断（只有小白才能做到！）

解题思路:利用取整取余得出a,b,c,d,e的值，判断a,b,c,d,e是否为0，进而输出结果。

注意事项：注意哪个"if"和哪个"else"对应，别搞混了（我自己看着都晕，我加个注释吧）

参考代码:

#include<stdio.h>

int main()

{

    int a,b,c,d,e,sum1;

    scanf("%d",&sum1);

    a=sum1/10000;

    b=sum1/1000%10;

    c=sum1/100%10;

    d=sum1/10%10;

    e=sum1%10;

    if(a==0) //1

    {

        if(b==0) //2

        {

            if(c==0) //3

            {

                 if(d==0) //4

                {

                    printf("1\n");

                    printf("%d\n",e);

                    printf("%d",e);

                 }

                else //4

                {

                    printf("2\n");

                    printf("%d %d\n",d,e);

                    printf("%d",10*e+d);

                }

            }

            else //3

            {

                printf("3\n");

                printf("%d %d %d\n",c,d,e);

                printf("%d",100*e+10*d+c);

            }

        }

        else //2

        {

            printf("4\n");

            printf("%d %d %d %d\n",b,c,d,e);

            printf("%d",e*1000+d*100+c*10+b);

        }

    }

    else //1

    {

    printf("5\n");

    printf("%d %d %d %d %d\n",a,b,c,d,e);

    printf("%d",e*10000+d*1000+c*100+b*10+a);

    }

return 0;

}