简单好理解

解题思路:将单词分开，并存在在二维数组中

注意事项:

参考代码:

#include<stdio.h>

#include<string.h>

int main()

{

        int k = 0, j = 0;  

        int conut = 0;

        char ch[150] = { 0 };

        char ch1[150][150] = { 0 };

        gets(ch);

         for (int i = 0; i < strlen(ch); i++)

         {

                 if (ch[i] != ' ')    

                 {

                        ch1[k][j++] = ch[i];

                 }

                 else if (ch[i] == ' ')

                  {

                         k++;

                         j = 0;

                 }

         }

         int i, r;

         int flag = 0;  //标记

         for (i = 0; i <= k; i++)

         {

                  flag = i;

                  for (r = i + 1; r <= k; r++)

                  {

                         if (strcmp(ch1[i], ch1[r]) == 0)   //前面与后面重复的，直接跳出

                          {

                          flag ++;

                          break;

                          }

                  }

                  if (flag == i)

                  {

                         conut++;

                  }        

         }

         printf("%d\n", conut);

         return 0;

}