解题思路: 先用字符类的指针数组保存24个小时,分数在24之外的部分可以构造;
注意事项: 第一思路,也可用map容器求解,不过大致思路差不多
参考代码:
#include<iostream> using namespace std; char *twenty[24]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty","twenty one","twenty two","twenty three"}; void check(int hh,int mm) { cout<<twenty[hh]<<" ";//输出小时,此后多行用于输出,或构造输出分钟 if(mm==0)//整点输出需要"o'clock" cout<<"o'clock"; if(mm>0&&mm<=24)//前24个数不用构造,数组里面有 cout<<twenty[mm]; if(mm>24&&mm<30) { cout<<"twenty"; cout<<" "<<twenty[mm%10]; } if(mm>=30&&mm<40) { cout<<"thirty";//30,31,32...都要输出thirty if(mm>30)//31,32,32...需要多输出1个尾数 { cout<<" "<<twenty[mm%10];//输出尾数,此后同理 } } if(mm>=40&&mm<50) { cout<<"forty"; if(mm>40) { cout<<" "<<twenty[mm%10]; } } if(mm>=50&&mm<60) { cout<<"fifty"; if(mm>50) { cout<<" "<<twenty[mm%10]; } } } int main() { int hour,minite; cin>>hour>>minite; check(hour,minite); return 0; }
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