第1049题，巧妙利用Switch不加break

解题思路:

注意事项:闰年：能被四整除同时不被100整除，或能被400整除

year%4==0&&year%100||year%400==0
参考代码:

#include<stdio.h>

struct date{

int year;

int month;

int day;

};

int main(void)

{

struct date des;

int ans=0;

scanf("%d%d%d",&des.year,&des.month,&des.day);

if(des.year%4==0&&des.year%100||des.year%400==0)

{

switch(des.month)

{

case 12:ans+=30;

case 11:ans+=31;

case 10:ans+=30;

case 9:ans+=31;

case 8:ans+=31;

case 7:ans+=30;

case 6:ans+=31;

case 5:ans+=30;

case 4:ans+=31;

case 3:ans+=29;

case 2:ans+=31;

break;

}

}

else

{

switch(des.month)

{

case 12:ans+=30;

case 11:ans+=31;

case 10:ans+=30;

case 9:ans+=31;

case 8:ans+=31;

case 7:ans+=30;

case 6:ans+=31;

case 5:ans+=30;

case 4:ans+=31;

case 3:ans+=28;

case 2:ans+=31;

break;

}

}

ans+=des.day;

printf("%d",ans);

return 0;

}