循环和if()语句

解题思路:

注意事项:

参考代码: 

    #include<stdio.h>

    int main () {

        int x,n;

        scanf("%d",&x);

        while(1){

            if(x%2==0&&x/2!=1){

                n=x/2;

                printf("%d/2=%d\n",x,n);

                x=n;

            }

            else if(x/2==1){

                printf("%d/2=1",x);

                break;

            }

            else{

                n=x*3+1;

                printf("%d*3+1=%d\n",x,n);

                x=n;

            }

    }

        return 0;

}