C语言训练-百钱百鸡问题 百钱白鸡

解题思路:

注意事项:

参考代码:

#include

int main()

{

int x3;

int x1, x2;

for (x3 = 75; x3 <= 85; x3++)

{

if ((4 * x3 - 300) / 3 != (4 * x3 - 300) / 3.0) continue; // 判断是否是整数 

if ((600 - 7 * x3) / 3 != (600 - 7 * x3) / 3.0) continue; // 判断是否是整数

x1 = (4 * x3 - 300) / 3;

x2 = (600 - 7 * x3) / 3;

if (x1 + x2 + x3 == 100 && (5 * x1 + 3 * x2 + x3 / 3.0) == 100)

{

    printf("cock=%d,hen=%d,chicken=%d\n", x1, x2, x3);

}

}

return 0;

}