1051: [编程入门]结构体之成绩统计2——超详细注释

解题思路:

注意事项:

参考代码:

n = int(input())

l = [[0] * 5]*n

#列表赋初始值

for i in range(n):

    l[i] = [_ for _ in input().split()]

#三科的平均成绩

av1,av2,av3 = 0,0,0

for i in range(n):

    av1 += int(l[i][2])/n

    av2 += int(l[i][3])/n

    av3 += int(l[i][4])/n

print(int(av1),int(av2),int(av3))

#最高分学生成绩

ls = [0]*n #记录每位同学的总成绩

for i in range(n):

    ls[i]=int(l[i][2])+int(l[i][3])+int(l[i][4])

#找出最高分同学对应的下标    

max_ = 0

for i in range(n):

    if ls[i] > ls[max_]:

        max_ = i

#输出

for i in l[max_]:

    print(i,end = ' ')