C语言训练-求PI*

i=n=pi=1
while 1:
    if (1/(i+2))<0.000001:
        break
    if n%2==0:
        pi+=1/(i+2)
    elif n%2:
        pi-=1/(i+2)
    i+=2
    n+=1
print('%.6f'%(pi*4))

解题思路:

注意事项:

参考代码: