python-判断名次

解题思路:

注意事项:

参考代码:

from itertools import permutations  
  
def f():  
    rst = tuple(permutations('ABCDE'))  
    words = []        #记录A~E所说的话的内容
    for  i in range(5):  
        words = words + [input().strip()]  
  
    cnt = 0  
    for item in rst:  
        dict = {'A':0,'B':1,'C':2,'D':3,'E':4}     #A~E是按照次数讲话的
        flag = 1     #筛选本次排列是否复合条件的一个标记
        for i in range(5):  
            x = dict[item[i]]       #记录排在第i名的字母
            alpha = words[x][0]     #读取这个字母说过的话
            num = int(words[x][-1])  
            if i in (0,2,4):        #如果说话人的名词在奇数名，因为数组下标以0开头，所以此处为（0，2，4）
                if words[x][1] == '=':  
                    if item.index(alpha)+1 == num:  
                        flag = 0  
                        break  
                elif words[x][1] == '!':  
                    if item.index(alpha)+1 != num:  
                        flag = 0  
                        break  
                elif words[x][1] == '>' and words[x][2] != '=':  
                    if item.index(alpha)+1 > num:  
                        flag = 0  
                        break  
                elif words[x][1] == '<' and words[x][2] != '=':  
                    if item.index(alpha)+1 < num:  
                        flag = 0  
                        break  
                elif words[x][1:3] == '>=':  
                    if item.index(alpha)+1 >= num:  
                        flag = 0  
                        break  
                elif words[x][1:3] == '<=':  
                    if item.index(alpha)+1 <= num:  
                        flag = 0  
                        break  
            else:  
                if words[x][1] == '=':  
                    if item.index(alpha)+1 != num:  
                        flag = 0  
                        break  
                elif words[x][1] == '!':  
                    if item.index(alpha)+1 == num:  
                        flag = 0  
                        break  
                elif words[x][1] == '>' and words[x][2] != '=':  
                    if item.index(alpha)+1 <= num:  
                        flag = 0  
                        break  
                elif words[x][1] == '<' and words[x][2] != '=':  
                    if item.index(alpha)+1 >= num:  
                        flag = 0  
                        break  
                elif words[x][1:3] == '>=':  
                    if item.index(alpha)+1 < num:  
                        flag = 0  
                        break  
                elif words[x][1:3] == '<=':  
                    if item.index(alpha)+1 > num:  
                        flag = 0  
                        break  
        if flag:  
            print(''.join(item))  
            cnt = cnt + 1  
    print(cnt)  
  
  
if __name__ == '__main__':  
    f()