数组的距离

解题思路:采用嵌套循环将其差值用数组存储在进行绝对值处理最后排序

注意事项:
这里引用了一个变量a，起到一个指针的作用

参考代码:

import java.util.Arrays;

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

Scanner scanner=new Scanner(System.in);

while (scanner.hasNext()) {

int n=scanner.nextInt();

int m=scanner.nextInt();

int arr1[]=new int[n];

int arr2[]=new int[m];

for (int i = 0; i < arr1.length; i++) {

arr1[i]=scanner.nextInt();

}

for (int i = 0; i < arr2.length; i++) {

arr2[i]=scanner.nextInt();

}

int a=0;

int arr3[]=new int[n*m];

for (int i = 0; i < arr1.length; i++) {

for (int j = 0; j < arr2.length; j++) {

arr3[a]=arr1[i]-arr2[j];

a++;

}

}

for (int i = 0; i < arr3.length; i++) {

arr3[i]=Math.abs(arr3[i]);

}

//排序

Arrays.sort(arr3);

System.out.println(arr3[0]);

}

}

}