解题思路:
注意事项:
参考代码:
import java.util.Scanner;
public class A1115 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int[] arr1 = new int[n];
int[] arr2 = new int[n];
for (int i = 0; i < n; i++) {
arr1[i] = sc.nextInt();
arr2[i] = sc.nextInt();
}
for (int i = 0; i < n; i++) {
String[][] arrs = new String[arr1[i]][arr1[i] * arr2[i]];
for (int j = 0; j < arr2[i]; j++) {
if(j==0) {
for (int k = 0; k < arr1[i]; k++) {
for (int l = 0; l < arr1[i]; l++) {
if ((k == l || k == arr1[i] - l - 1) && k + 1 != arr1[i] / 2 + 1) {
arrs[k][l] = "X";
System.out.print(arrs[k][l]);
continue;
}
if (k + 1 == arr1[i] / 2 + 1) {
arrs[k][l] = " ";
arrs[k][k] = "X";
System.out.print(arrs[k][l]);
continue;
}
arrs[k][l] = " ";
System.out.print(arrs[k][l]);
}
System.out.println();
}
}else {
for (int k = 1; k < arr1[i]; k++) {
for (int l = 0; l < arr1[i]; l++) {
if ((k == l || k == arr1[i] - l - 1) && k + 1 != arr1[i] / 2 + 1) {
arrs[k][l] = "X";
System.out.print(arrs[k][l]);
continue;
}
if (k + 1 == arr1[i] / 2 + 1) {
arrs[k][l] = " ";
arrs[k][k] = "X";
System.out.print(arrs[k][l]);
continue;
}
arrs[k][l] = " ";
System.out.print(arrs[k][l]);
}
System.out.println();
}
}
}
System.out.println();
}
}
}
0.0分
0 人评分
C语言网提供由在职研发工程师或ACM蓝桥杯竞赛优秀选手录制的视频教程,并配有习题和答疑,点击了解:
一点编程也不会写的:零基础C语言学练课程
解决困扰你多年的C语言疑难杂症特性的C语言进阶课程
从零到写出一个爬虫的Python编程课程
只会语法写不出代码?手把手带你写100个编程真题的编程百练课程
信息学奥赛或C++选手的 必学C++课程
蓝桥杯ACM、信息学奥赛的必学课程:算法竞赛课入门课程
手把手讲解近五年真题的蓝桥杯辅导课程
发表评论 取消回复