C语言训练-尼科彻斯定理,可输入999999

解题思路:

注意事项:

参考代码:

n = int(input())

a=int(n**3)

b=int(a/n)

ls=[]

if n%2==0:

   for i in range((b-int(n/2)*2+1),(b+(int(n/2))*2),2):

       ls.append(i)

if n%2 != 0:

    for i in range(b-2*(int((n-1)/2)),b+2*(int((n-1)/2))+1,2):

        ls.append(i)

d = []

for i in ls:

    d.append('+'+str(i))

d[0]=str(ls[0])

print(f"{str(n)}*{str(n)}*{str(n)}={a}=",end='')

for i in d:

    print(i,end='')