解题思路:分奇偶情况讨论
注意事项:输出次数的计算
参考代码:
#include<iostream>
using namespace std;
int main()
{
int n, m;
while (cin>>n>>m)
{
if (n % m == 0)
{
for (int i = 0; i < n/m; i++)//输出次数
{
int sum = 0, a = i * 2*m;
for (int j = 0; j < m; j++)
{
a += 2;
sum += a;
}
cout << sum / m << " ";
}
}
else
{
for (int i = 0; i < n/m; i++)//输出次数
{
int sum = 0, a = i * 2*m;
for (int j = 0; j < m; j++)
{
a += 2;
sum += a;
}
cout << sum / m << " ";
}
int a = (n / m) * 2*m,sum=0;
for (int i = 0; i < n % m; i++)
{
a += 2;
sum += a;
}
cout << sum / (n % m);
}
cout << endl;
}
return 0;
}
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