字符串分类统计另一种方法

解题思路:

注意事项:

参考代码:

int count1=0,count2=0,count3=0,count4=0;

int i;

char str[200];

gets(str);

for(i=0;str[i]!='\0';i++)

{

if(('a'<=str[i]&&str[i]<='z')||('A'<=str[i]&&str[i]<='Z'))

{

count1++;

continue;

}

    if('0'<=str[i]&&str[i]<='9')

{

count2++;

continue;

}

if(str[i]==' ')

{

count3++;

continue;

}

count4++;

}

printf("%d\t%d\t%d\t%d\t\n",count1,count2,count3,count4);

return 0;