题解 1010：利润计算

解题思路:
使用条件运算符
注意事项:

参考代码:

#include<stdio.h>

int main()

{

    int num=0;

    int profit=0;

    scanf("%d",&num);

    profit=num<=100000?num*0.1:

    num<=200000?100000*0.1+(num-100000)*0.075:

    num<=400000?100000*0.1+100000*0.075+(num-200000)*0.05:

    num<=600000?100000*0.1+100000*0.075+200000*0.05+(num-400000)*0.03:

    num<=1000000?100000*0.1+100000*0.075+200000*0.05+200000*0.03+(num-600000)*0.015:

    100000*0.1+100000*0.075+200000*0.05+200000*0.03+400000*0.015+(num-1000000)*0.01;

    printf("%d",profit);

    return 0;

}