结构体之时间设计C语言

解题思路:这是最容易想到的解法，把每种情况列举出来。

注意事项:

参考代码:

#include <stdio.h>

struct Stu

{

int year;

int month;

int date;

};

int main()

{

struct Stu stu = { 0, 0, 0 };

scanf("%d%d%d", &stu.year, &stu.month, &stu.date);

if (stu.year % 400 == 0 || stu.year % 100 != 0 && stu.year % 4 == 0)

{

switch (stu.month)

{

case 1:

{

  printf("%d\n", stu.date);

  break;

}

case 2:

{

  printf("%d\n", 31 + stu.date);

  break;

}

case 3:

{

  printf("%d\n", 31 + 29 + stu.date);

  break;

}

case 4:

{

  printf("%d\n", 31 + 29 + 31 + stu.date);

  break;

}

case 5:

{

  printf("%d\n", 31 + 29 + 31 + 30 + stu.date);

  break;

}

case 6:

{

  printf("%d\n", 31 + 29 + 31 + 30 + 31 + stu.date);

  break;

}

case 7:

{

  printf("%d\n", 31 + 29 + 31 + 30 + 31 + 30 + stu.date);

  break;

}

case 8:

{

  printf("%d\n", 31 + 29 + 31 + 30 + 31 + 30 + 31 + stu.date);

  break;

}

case 9:

{

  printf("%d\n", 31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + stu.date);

  break;

}

case 10:

{

   printf("%d\n", 31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + stu.date);

   break;

}

case 11:

{

   printf("%d\n", 31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + stu.date);

   break;

}

case 12:

{

   printf("%d\n", 31 + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + stu.date);

   break;

}

}

}

else

{

switch (stu.month)

{

case 1:

{

  printf("%d\n", stu.date);

  break;

}

case 2:

{

  printf("%d\n", 31 + stu.date);

  break;

}

case 3:

{

  printf("%d\n", 31 + 28 + stu.date);

  break;

}

case 4:

{

  printf("%d\n", 31 + 28 + 31 + stu.date);

  break;

}

case 5:

{

  printf("%d\n", 31 + 28 + 31 + 30 + stu.date);

  break;

}

case 6:

{

  printf("%d\n", 31 + 28 + 31 + 30 + 31 + stu.date);

  break;

}

case 7:

{

  printf("%d\n", 31 + 28 + 31 + 30 + 31 + 30 + stu.date);

  break;

}

case 8:

{

  printf("%d\n", 31 + 28 + 31 + 30 + 31 + 30 + 31 + stu.date);

  break;

}

case 9:

{

  printf("%d\n", 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + stu.date);

  break;

}

case 10:

{

   printf("%d\n", 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + stu.date);

   break;

}

case 11:

{

   printf("%d\n", 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + stu.date);

   break;

}

case 12:

{

   printf("%d\n", 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + stu.date);

   break;

}

}

}

return 0;

}